Solutions to Harder Problem Sums Involving Fractions and Ratios

Solution to FracRatio1:

Sally spent 1⁄3 of her money on a dress and another 1⁄4 of her money on a bag. She had $134 left. How much did she spend on the dress?
To be able to compare the units for the dress and the bag, we need to make the denominators the same.
We find the LCM of 3 and 4, which is 12.
         1⁄3 = 4⁄12                           1⁄4  =  3⁄12 
Since the total number of units is 12, number of units for the money left is 12u - 4u - 3u = 5u

5 units
à $340

1 unit à $340 ÷ 5 = $68
4 units à 4 × $68 = $272





















Solution to FracRatio2:

A class had an equal number of boys and girls at first. After 8 boys and 2 girls left the class,  the number of boys was  3⁄5 of the number of girls in the class. How many boys were in the class at first?
8 – 2  à 6
2 units à 6
1 unit à 6 ÷ 2 = 3
3 units à 3 × 3 = 9
9 + 8 = 17                      Ans: 17 boys





















Solution to FracRatio3:

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